x/(4x+x^2)

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Solution for x/(4x+x^2) equation: 


D( x )

x^2+4*x = 0

x^2+4*x = 0

x^2+4*x = 0

x^2+4*x = 0

DELTA = 4^2-(0*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-4)/(1*2) or x = (-16^(1/2)-4)/(1*2)

x = 0 or x = -4

x in (-oo:-4) U (-4:0) U (0:+oo)

x/(x^2+4*x) = 0

x^2+4*x = 0

x*(x+4) = 0

x+4 = 0 // - 4

x = -4

x*(x+4) = 0

x/(x*(x+4)) = 0

x = 0

x in { 0} 

x belongs to the empty set

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